3.739 \(\int x^{-4+n} (a+b x)^{-n} \, dx\)

Optimal. Leaf size=110 \[ -\frac{2 b^2 x^{n-1} (a+b x)^{1-n}}{a^3 (1-n) (2-n) (3-n)}+\frac{2 b x^{n-2} (a+b x)^{1-n}}{a^2 (2-n) (3-n)}-\frac{x^{n-3} (a+b x)^{1-n}}{a (3-n)} \]

[Out]

-((x^(-3 + n)*(a + b*x)^(1 - n))/(a*(3 - n))) + (2*b*x^(-2 + n)*(a + b*x)^(1 - n
))/(a^2*(2 - n)*(3 - n)) - (2*b^2*x^(-1 + n)*(a + b*x)^(1 - n))/(a^3*(1 - n)*(2
- n)*(3 - n))

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Rubi [A]  time = 0.0950628, antiderivative size = 110, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.133 \[ -\frac{2 b^2 x^{n-1} (a+b x)^{1-n}}{a^3 (1-n) (2-n) (3-n)}+\frac{2 b x^{n-2} (a+b x)^{1-n}}{a^2 (2-n) (3-n)}-\frac{x^{n-3} (a+b x)^{1-n}}{a (3-n)} \]

Antiderivative was successfully verified.

[In]  Int[x^(-4 + n)/(a + b*x)^n,x]

[Out]

-((x^(-3 + n)*(a + b*x)^(1 - n))/(a*(3 - n))) + (2*b*x^(-2 + n)*(a + b*x)^(1 - n
))/(a^2*(2 - n)*(3 - n)) - (2*b^2*x^(-1 + n)*(a + b*x)^(1 - n))/(a^3*(1 - n)*(2
- n)*(3 - n))

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Rubi in Sympy [A]  time = 15.7367, size = 76, normalized size = 0.69 \[ - \frac{x^{n - 3} \left (a + b x\right )^{- n + 1}}{a \left (- n + 3\right )} + \frac{2 b x^{n - 2} \left (a + b x\right )^{- n + 1}}{a^{2} \left (- n + 2\right ) \left (- n + 3\right )} - \frac{2 b^{2} x^{n - 1} \left (a + b x\right )^{- n + 1}}{a^{3} \left (- n + 1\right ) \left (- n + 2\right ) \left (- n + 3\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate(x**(-4+n)/((b*x+a)**n),x)

[Out]

-x**(n - 3)*(a + b*x)**(-n + 1)/(a*(-n + 3)) + 2*b*x**(n - 2)*(a + b*x)**(-n + 1
)/(a**2*(-n + 2)*(-n + 3)) - 2*b**2*x**(n - 1)*(a + b*x)**(-n + 1)/(a**3*(-n + 1
)*(-n + 2)*(-n + 3))

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Mathematica [A]  time = 0.0692235, size = 64, normalized size = 0.58 \[ \frac{x^{n-3} (a+b x)^{1-n} \left (a^2 \left (n^2-3 n+2\right )+2 a b (n-1) x+2 b^2 x^2\right )}{a^3 (n-3) (n-2) (n-1)} \]

Antiderivative was successfully verified.

[In]  Integrate[x^(-4 + n)/(a + b*x)^n,x]

[Out]

(x^(-3 + n)*(a + b*x)^(1 - n)*(a^2*(2 - 3*n + n^2) + 2*a*b*(-1 + n)*x + 2*b^2*x^
2))/(a^3*(-3 + n)*(-2 + n)*(-1 + n))

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Maple [A]  time = 0.008, size = 77, normalized size = 0.7 \[{\frac{ \left ( bx+a \right ){x}^{-3+n} \left ({a}^{2}{n}^{2}+2\,abnx+2\,{b}^{2}{x}^{2}-3\,{a}^{2}n-2\,abx+2\,{a}^{2} \right ) }{ \left ( bx+a \right ) ^{n} \left ( -3+n \right ) \left ( -2+n \right ) \left ( -1+n \right ){a}^{3}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int(x^(-4+n)/((b*x+a)^n),x)

[Out]

(b*x+a)*x^(-3+n)*(a^2*n^2+2*a*b*n*x+2*b^2*x^2-3*a^2*n-2*a*b*x+2*a^2)/((b*x+a)^n)
/(-3+n)/(-2+n)/(-1+n)/a^3

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Maxima [F]  time = 0., size = 0, normalized size = 0. \[ \int{\left (b x + a\right )}^{-n} x^{n - 4}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x^(n - 4)/(b*x + a)^n,x, algorithm="maxima")

[Out]

integrate((b*x + a)^(-n)*x^(n - 4), x)

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Fricas [A]  time = 0.229661, size = 140, normalized size = 1.27 \[ \frac{{\left (2 \, a b^{2} n x^{3} + 2 \, b^{3} x^{4} +{\left (a^{2} b n^{2} - a^{2} b n\right )} x^{2} +{\left (a^{3} n^{2} - 3 \, a^{3} n + 2 \, a^{3}\right )} x\right )} x^{n - 4}}{{\left (a^{3} n^{3} - 6 \, a^{3} n^{2} + 11 \, a^{3} n - 6 \, a^{3}\right )}{\left (b x + a\right )}^{n}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x^(n - 4)/(b*x + a)^n,x, algorithm="fricas")

[Out]

(2*a*b^2*n*x^3 + 2*b^3*x^4 + (a^2*b*n^2 - a^2*b*n)*x^2 + (a^3*n^2 - 3*a^3*n + 2*
a^3)*x)*x^(n - 4)/((a^3*n^3 - 6*a^3*n^2 + 11*a^3*n - 6*a^3)*(b*x + a)^n)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x**(-4+n)/((b*x+a)**n),x)

[Out]

Timed out

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GIAC/XCAS [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{n - 4}}{{\left (b x + a\right )}^{n}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x^(n - 4)/(b*x + a)^n,x, algorithm="giac")

[Out]

integrate(x^(n - 4)/(b*x + a)^n, x)